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The oxidation state of `Cr` in `K_(2)Cr_(2)O_(7)` is:

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The oxidation state of `Cr` in `K_(2)Cr_(2)O_(7)` is:
A. `+5`
B. `+3`
C. `+6`
D. `+7`
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Correct Answer - C
Let the oxidation state of Cr is x
`K_(2)Cr_(2)O_(7)`
`therefore 2(+1)+2x=7(-2)=0`
`2+2x-14=0`
`2x-12=0`
`2x=12`
`x=12/2 = +6`
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