Question

A glavanometer of `50 Omega` resistance has 25 divisions. A current of `4xx10^(-4)` A gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of `25 V`, it should be connected with a resistance of
A. `245Omega` in parallel
B. `2550Omega` in series
C. `2450Omega` in series
D. `2500Omega` in parallel.

Answer 1

Correct Answer - 3

According to question 25=`I(R+R_(g))`
` =(4xx10^(-4)xx25)(R+50)`
`rArr R+50=2500rArrR=2450Omega`