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If the power dissipated in `5Omega` is 20W then power dissipated in `4Omega` is:-

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If the power dissipated in `5Omega` is 20W then power dissipated in `4Omega` is:-
image
A. 4W
B. 6W
C. 10W
D. 20W
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1 Answer

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Best answer
`P=VI=V^(2)//R`, voltage constant
`Pprop1//R`
image
then power in ` 10Omega` will be 20W
when I constant then
`P=I^(2)RrArrPpropR`
`(P)/(10)=(4)/(10)rArrP=4W`
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