The correct option (D) 4 W
Explanation:
from figure, V = I1 ∙ 5 = I2 ∙ 10

∴ I1 = 2I2
Power decapitated = P = I2R
for 5Ω resistor, 20 = I12 × 5
I12 = 4
I1 = 2A
∴ I2 = (I1 / 2) = (2/2) = 1A
∴ Power dissipated across 4Ω resistor = I22 × R
= 12 × 4 = 4 W