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How much heat is required to change `10g` ice at `0^(@)C` to steam at `100^(@)C`? Latent heat of fusion and vaporisation for `H_(2)O` are `80 cl g^(-1)` and `540 cal g^(-1)`, respectively. Specific heat of water is `1cal g^(-1)`.

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Total heat absorbed
`=DeltaH_("fusion")+DeltaH_("temp. rise")+DeltaH_(vap)`.
`=10xx80+10xx1xx100+10xx540=7200cal`

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