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If 4nα = pi, then the value of tan α tan 2α tan 3α tan 4α................. tan (2α –2)α tan (2n – 1)α is (1) 0

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If 4nα = pi, then the value of tan α tan 2α tan 3α tan 4α................. tan (2α –2)α tan (2n – 1)α is

(1) 0 

(2) 1 

(3) –1 

(4) None of these

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1 Answer

+1 vote
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Best answer

Correct option (2) 1 

Explanation :

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