Question

The equivalent constant of the reaction:
`Cu(s)+2Ag^(+)(aq.) rarr Cu^(2+)(aq.)+2Ag(s)`
`E^(@)=0.46 V` at `298 K`,is:
A. `2.0 xx 10^(10)`
B. `4.0xx10^(10)`
C. `4.0xx10^(15)`
D. `2.4xx10^(10)`

Answer 1

Correct Answer - C
K= antilog `[(nE^(@))/0.059]=` antilog `[(2xx0.46)/0.059]`
= antilog 15.593
`=3.9xx10^(15)`
`~~ 4xx10^(15)`