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Evaluate `lim_(xto0) (tan2x-x)/(3x-sinx).`

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Correct Answer - `1//2`
`underset(xto0)lim(tan2x-x)/(3x-sinx)=underset(xto0)lim{((2tan2x)/(2x)-1)/(3-(sinx)/(x))}=1/2`

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