Evaluate `lim_(ntooo)ncos((pi)/(4n))sin((pi)/(4n)).`

Correct Answer - `pi//4`
`L=underset(ntooo)limncos((pi)/(4n))sin((pi)/(4n))`
`=underset(ntooo)lim(cos((pi)/(4n))sin((pi)/(4n)))/(((pi)/(4n))4/pi)`
`=cos(0)xx1xx(pi)/(4)=(pi)/(4)`

Evaluate `lim_(ntooo)ncos((pi)/(4n))sin((pi)/(4n)).`

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