We have `y = f(x) = tan^(2) x`
Period of the function is `pi`.
Function is even, so the graph is symmetrical above the x - axis.
Let us draw the graph for `0 lt x lt pi//2`.
For `0 lt x lt pi//4, 0 lt tan x lt 1`
`therefore` `tan^(2) x lt tan x`
For `x gt pi//4`
`tan x gt 1`
`therefore` `tan^(2) x gt tan x`
Hence the graph of `y = tan^(2) x` lies below and above the graph of y = tan x for `x in (0, pi//4)` and `x in (pi//4, pi//2)`.
So the graph of the function for `x in (-pi//2, pi//2)` is as shown in the following figure.
Since the function has period `pi` , the graph of the function is as shown in the following figure.
