Correct Answer - `36pi` sq. unit
In the figure, circumcircle of equilateral triangle ABC has circumference `24pi`.
Let R be the radius of the circle and O be the centre.
`:. 2piR=24pi`
`rArr R=12`
Circle inscribed in triangle touches BC at D, which is midpoint of BC.
In triangle ODB, `sin30^(@)=(OD)/(OB)=r/R` (r is the radius of incircle)
`:. r=12/2=6`
`:." Area of inscrived circle "=pir^2=36pi" sq. unit"`