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There is an equilateral triangle with side 4 and a circle with the centre on one of the vertex of that triangle. The arc of that circle divides the triangle into two parts of equal area. How long is the radius of the circle?

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Correct Answer - `sqrt((12sqrt3)/pi)`
From the eqestion, `sqrt3/4xx16=2xx1/2r^2xxpi/3`
`pir^2=12sqrt3orr=sqrt(12sqrt3)/pi`

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