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Identify the correct variation of potential energy U as a function of displacement x from mean

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Identify the correct variation of potential energy U as a function of displacement x from mean position of a harmonic oscillator (U at mean position = 0)

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Correct option (c)

Explanation :

U = kx2/2

y = mx , is a straight line passing through origin. The answer will be (d) as x2 cannot have negative value (for real x)

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