This is to be handled by the same trick as in Q.96. We have effectively a two-dimensional situation. For a uniform cylinder full of charge with charge density ρ0 (charge per unit volume), the electric field E at an inside point is along the (cylindrical) radius vector and equal to,
![](https://www.sarthaks.com/?qa=blob&qa_blobid=5761594098027109049)
Therefore the polarized cylinder can be thought of as two equal and opposite charge distributions displaced with respect to each other
![](https://www.sarthaks.com/?qa=blob&qa_blobid=13639345204754600621)
(direction of electric dipole moment vector being from the negative charge to positive charge .)