Given :
B.E. of 58Ni = 508 MeV,
A = 58
To find :
Binding energy per nucleon \(\bar B\)
Formula :
\(\bar B\) = \(\frac{B.E}{A}\)
Calculation :
\(\bar B\) = \(\frac{508}{58}\)
= 8.75862069
≈ 8.76 MeV/nucleon
∴ Binding energy per nucleon of 58Ni is 8.76 MeV/nucleon.