Question

A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given an acceleration ‘a’ towards the right. The relation between a and θ for the block to remain stationary on the wedge is

(A) \(a=\frac{g}{cosec\,\theta}\)

(B) \(a=\frac{g}{sin\,\theta}\)

(C) a = g cos θ

(D) a = g tan θ

Answer 1

The mass of block is given to be m. It will remain stationary if forces acting on it are in equilibrium i.e., ma cos θ = mg sin θ

Here, ma = Pseudo force on block.

∴ a = g tan θ

a = g tan θ