If g = 9.8 m/s^2 on the surface of the Earth, find its value at h = R/2 from the Earth. surface of the Earth.

Question

If g = 9.8 m/s² on the surface of the Earth, find its value at h = \(\frac{R}{2}\) from the surface of the Earth.

Answer 1

Given: g = 9.8 m/s², h = \(\frac{R}{2}\)

To find: Acceleration due to gravity (g_h)

Formula: \(\frac{g_h}{g}=\frac{R^2}{(R+h)^2}\)

Calculation: From formula,

At h = \(\frac{R}{2}\) from the surface of the Earth, the value of g is 4.35 m/s².