Question

The amount of zinc required to produce 224 mL of H₂ at STP on treatment with dilute H₂SO₄ will be

(a) 65 g 

(b) 0.065g 

(c) 0.65 g 

(d) 6.5 g

Answer 1

The correct option is : (c) 0.65 g 

Explanation :

Since 65 g of zinc reacts to liberate 22400 mL of H₂, at STP, therefore amount of zinc needed to produce 224 mL of H₂ at STP

= 65/22400 x 224 = 0.65 g