Question

The amount of zinc (atomic weight 65) required to produce 224 ml of H₂ at S.T.P. on treatment with dilute H₂SO₄ will be

(a) 0.65 gm

(b) 6.5 gm

(c) 65 gm

(d) 0.065 gm

Answer 1

Correct option is (a) 0.65 gm

Zn + H₂SO₄ → ZnSO₄ + H₂

Wt. of Zn required to produce 224 ml (STP) = \(\frac{65 \times 224}{22400}\) = 0.65 g