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14.0 ग्राम `""_(7 )N ^(14 )` में कितने परमाणवीय इलेक्ट्रॉन, प्रोटॉन तथा न्यूट्रॉन हैं ? ( आवोग्रादो संख्या `=6xx10 ^(23 )` )

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Correct Answer - 14.0 ग्राम `""_(7 )N ^(14 )` में इलेक्ट्रॉन की संख्या = प्रोटॉनों की संख्या
= न्यूट्रॉनों की संख्या
=`7xx(6xx10^(23))`
=`42xx10^(23)`.

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