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14.0 ग्राम `._(7)N^(14)` में कितने परमाणवीय इलेक्ट्रॉन, प्रोटॉन तथा न्यूट्रॉन हैं?
(आवोगाद्रो संख्या `=6xx10^(23)`)

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`._(7)N^(14)` परमाणु में 7 इलेक्ट्रॉन, 7 प्रोटॉन तथा 7 न्यूट्रॉन हैं। 14.0 ग्राम `._(7)N^(14)` में परमाणुओं की संख्या `6xx10^(23)` होती है। अतः 14.0 ग्राम `._(7)N^(14)` में इलेक्ट्रॉनों की संख्या `=` प्रोटॉनों की संख्या
`=` न्यूट्रॉनों की संख्या `=7xx(6xx10^(23))`
`=42xx10^(23)`

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