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If sin 2A = λ sin 2B, then prove that  tan (A+B)/ tan (A-B) = λ+1/ λ-1

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If sin 2A = λ sin 2B, then prove that \(\frac {tan(A+B)}{tan(A-B)}=\frac{λ+1}{λ-1}\)

tan (A+B)/ tan (A-B) = λ+1/ λ-1

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Sin 2A = λ sin 2B

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