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Prove the following: 2 cos 2A + 1/ 2 cos 2A-1 = tan (60°+A) tan (60°-A)

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Prove the following:

\(\frac{2\,cos\,2A+1}{2\,cos\,2A-1}=tan(60°+A) tan (60°-A)\)

2 cos 2A + 1/ 2 cos 2A-1 = tan (60°+A) tan (60°-A)

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R.H.S = tan (60°+A) tan(60°-A)

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