Question

The rate of a gas phase reaction involving the conversion of reactant ‘i’ to product is expressed as ____

(a) (-ri)=-(frac{1}{V^2}frac{dN_i}{dt} )

(b) (-ri)=-(frac{1}{V}frac{dN_i}{dt} )

(c) (-ri)=-(frac{dN_i}{dt} )

(d) (-ri)=-V(frac{dN_i}{dt} )

Answer 1

Correct answer is (b) (-ri)=-(frac{1}{V}frac{dN_i}{dt} )

The best explanation: The rate of change of the gaseous component ‘i’ in due course of the reaction is the change in number of moles of ‘i’ per unit time per unit volume of the reaction mixture. Hence, (-ri)=-(frac{1}{V}frac{dN_i}{dt}. )