Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
53.4k views
in Physics by (24.1k points)

If 2 kg mass is rotating on a circular path of radius 0.8 m with angular velocity of 44 rad/sec. If radius of the path becomes 1 m, then what will be the value of angular velocity?

(a) 28.16 rad/sec 

(b) 19.28 rad/sec

(c) 8.12 rad/sec 

(d) 35.26 rad/sec

1 Answer

+1 vote
by (34.4k points)
selected by
 
Best answer

Correct option (a) 28.16 rad/sec 

Explanation :

Mass (m) = 2 kg; initial radius of the path

(r1) = 0.8 m; initial angular velocity

(ω1) = 44 rad/sec and final radius of the path

(r2) = 1 m,

Moment of inertia, I1 =  mr12 = 2 x (0.8)2

= 1.28 kg m2 and I2 = mr22 = 2 x (1)= 2kg m2 

Therefore from the law of conservation of angular momentum,

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...