Correct Answer - Option 4 : 2.116 × 10
-10 m
CONCEPT:
-
Bohr’s proposed that electrons orbited the nucleus in specific orbits or shells with a fixed radius.
- Mathematically, the allowed value of the atomic radius is given by the equation:
\(r_n=n^2\times r_0\)
Where n is a positive integer, r0 is the smallest allowed radius for the hydrogen atom also known as Bohr’s radius.
CALCULATION:
Given that \(r_0=0.529\times 10^{-10}\,m\)
\(r_n=n^2\times 0.529\times 10^{-10}\,m\)
put n = 1
\(r_1=1^2\times 0.529\times 10^{-10}\,m=0.529\times 10^{-10}\,m\)
Similarly put n = 2, 3, 4 .........
\(r_2=2^2\times 0.529\times 10^{-10}\,m=2.116\times 10^{-10}\,m\)
\(r_3=3^2\times 0.529\times 10^{-10}\,m=4.761\times 10^{-10}\,m\)
we can get different values.
The minimum value of r for n = 1, will be
\(r_1=0.529\times 10^{-10}\,m\)
In the options other than option 4, all the values are less than the minimum value of radius.
However, putting n = 2 we are getting radius \(r_2=2.116\times 10^{-10}\,m\) i.e. option 4.
Hence the correct answer is option 4.