Correct Answer - Option 2 : Both A and R are individually true but R is
not the correct explanation of A
Explanation-
In electronics and semiconductor physics, the law of mass action is a relation between the concentrations of free electrons and electron holes under thermal equilibrium.
It states that, under thermal equilibrium, the product of the free electron concentration {n} and the free hole concentration {p} is equal to a constant square of intrinsic carrier concentration. The intrinsic carrier concentration is a function of temperature.
From Mass Action law:
\(np = n_i^2\)
Where, ni = intrinsic carrier concentration
n = tree electron concentration
p = hole concentration
\(n_i^2 = {A_0}{T^3}{e^{\frac{{ - Eg}}{{KT}}}}\)
\(n_i^2 \propto {T^3}\)
\({n_i} \propto {T^{\frac{3}{2}}}\)
For intrinsic semiconductor n = p = ni
Hence,
\(\left. {\begin{array}{*{20}{c}} {n \propto {T^{\frac{3}{2}}}}\\ {p \propto {T^{\frac{3}{2}}}} \end{array}} \right\}\)
So on increasing temperature free e- and hole concentration will increase in an intrinsic semiconductor
So both statements are true but R is not the correct explanation of A.