Correct Answer - Option 3 : 15 m
2
Method 1:
Area = (side) 2 or A = x2
\(\frac{{dA}}{{dx}} = 2 \times x\)
\(dA = 2 \times x \times dx\) {dx is error in length and dA is error in area}
\(dA = 2 \times 150\; \times \left( { \pm \;0.05} \right)\) = ± 15 m2
∴ Error in area = ± 15 m2
Method 2:
Initial area = 150 × 150 = 22500 m2
True Length, L = given length ± error
So we get L1 = 150+ 0.05 = 150.05 m or L2 = 150-0.05 = 149.95 m
True area, A1 = (150.05)2 = 22515.0025 m2 or A2 = (149.05)2 = 22485.0025 m2
Error = A1-A or A2 – A
Error = 22515.0025 – 22500 or 22485.0025-22500
Error = + 15.0025 m2 ≈ 15 m2 or – 14.9975 m2 ≈ -15 m2
We will get same answer.