Correct Answer - Option 3 : ± 12.6 m
2
Given: Diameter = 160 m
Error in diameter, ed = ± 0.05 m
Initial Area, \({A_i} = \frac{\pi }{4}{d^2} = \frac{\pi }{4} \times {\left( {160} \right)^2} = \) 20106.19 m3
Find area, \({A_g} = \frac{\pi }{4}{\left( {d \pm {e_d}} \right)^2} = \frac{\pi }{4}{\left( {160 \pm 0.05} \right)^2}\)
= 20118.76 m2 (+ve sign)
= 20093.62 m2 (-ve Sign)
Error in Area = Initial value – Find value
= 20106.19 – 20093.62
= + 12.56 m2