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Five numbers 10, 7, 5, 4 and 2 are to be arranged in a sequence from left to right following the directions given below:

1. No two odd or even numbers are next to each other.

2. The second number from the left is exactly half of the left-most number.

3. The middle number is exactly twice the right-most number.

Which is the second number from the right?


1. 2
2. 4
3. 7
4. 10

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Correct Answer - Option 3 : 7

Five numbers 10, 7, 5, 4 and 2 are to be arranged in a sequence from left to right.

1. No two odd or even numbers are next to each other.

As there are three even numbers in the sequence and no two even numbers can’t appear next to each other, we need to arrange even numbers in first, third and fifth positions.

The odd numbers will get arrange in second and fourth position.

2. The second number from the left is exactly half of the left-most number.

Left most position is even number, and second number form left is odd number. So, the only possibility to hold above condition is 10 and 5.

Sequence: 10 5 _ _ _

We need to fill the fourth position with an odd number. So, 7 will appear at fourth position.

Sequence: 10 5 _ 7 _

3. The middle number is exactly twice the right most number

Now, the remaining numbers are 4 and 2.

4 is exactly twice of 2.

So, the right most number will be 2 and the middle number will be 4.

Sequence: 10 5 4 7 2

The second number from right is 7.

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