Question

In a sequence of 12 consecutive odd numbers, the sum of the first 5 numbers is 425. What is the sum of the last 5 numbers in the sequence?

Answer 1

Concept:

In a consecutive series

\(\frac{{sum\,of\,numbers}}{{total\;numbers}} = middle\;number\;of\;the\;series\)

Calculation:

As 425 is the sum of the first 5 consecutive odd numbers

∴ \(\frac{{425}}{5}\) = 85 is the middle of 5 numbers i.e. 3^rd number.

∴ Series is 81, 83, 85, 87,…….101, 103

Sum of last 5 number is 95 + 97 + 99 + 101 + 103 = 495