Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
24.9k views
in Mathematics by (34.4k points)

If f(x) = 3x2 + 12x - 1, -1 ≤ ≤ 2

f(x) = 37 - x, 2 < x ≤ 3

(a) f(x) is increasing on [-1, 2]

(b) f(x) is continuous on [-1, 3]

(c) f'(2) does not exist

(d) f(x) has the maximum value at x = 2 

1 Answer

0 votes
by (24.1k points)
selected by
 
Best answer

Correct option 

(a) f(x) is increasing on [-1, 2]

(b) f(x) is continuous on [-1, 3]

(c) f'(2) does not exist

(d) f(x) has the maximum value at x = 2 

Explanation :

Again function is a algebraic polynomial, therefore, it is continuous at x  (-1, 2) and (2, 3) and for continuity at x = 2.

Again f(x) is increasing on [-1, 2] and is decreasing on (2, 3), it shows that f(x) has a maximum value at x =2.

Therefore, options (a), (b), (c), (d) are all correct.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...