Question

Attempt this question on graph paper. Marks obtained by 200 students in examination are given below :

Marks	0-10	10-20	20-30	30-40	40-50	50-60	60-70	70-80	80-90	90- 100
No. of Students	5	10	14	21	25	34	36	27	16	12

Draw an Ogive for the given distribution taking 2 cm =10 marks on one axis  and 2 cm = 20 students on the other axis. 

From the graph find:  

(i) the Median 

(ii) the Upper Quartile 

(iii) Number of students scoring above 65 marks. 

(iv) If 10 students qualify for merit scholarship, find the minimum marks  required to qualify.

Answer 1

(i) Here, n (number of students) = 200 (even)

(iii) No. of students scoring above 65 marks 

= Total No. of students - No. of students scoring less than or equal to 65 marks 

= 200-126 

= 74 (approx.)

(iv) From the graph, we observe the students from 191 to 200 qualify for merit scholarship. 

∴ The student who qualifies for merit scholarship scores more than 91 marks. 

∴ The minimurn marks required to qualify for merit scholarship 

= 92 (approx.)