Correct Answer - Option 3 : C
Calculation:
Improvement in marks of student A from 1st to 6th semester = [(86 – 74)/74 × 100]
⇒ (12/74 × 100)
⇒ 16.21%
Improvement in marks of student B from 1st to 6th semester = [(69 – 55)/55 × 100]
⇒ (14/55 × 100)
⇒ 25.45%
Improvement in marks of student C from 1st to 6th semester = [(66 – 40)/40 × 100]
⇒ (26/40 × 100)
⇒ 65%
Improvement in marks of student D from 1st to 6th semester = [(57 – 59)/59 × 100]
⇒ (-2/59 × 100)
⇒ -3.38%
Improvement in marks of student E from 1st to 6th semester = [(92 – 66)/66 × 100]
⇒ (26/66 × 100)
⇒ 39.39%
∴ Student C has the highest percentage of improvement from the 1st to 6th semester