Question

Oxygen to acetylene ratio in case of neutral flame by weight is

1. 0.8 ∶ 1.0
2. 3 ∶ 1
3. 1.2 ∶ 1
4. 2 ∶ 1

Answer 1

Correct Answer - Option 2 : 3 ∶ 1

Explanation:

Oxygen to acetylene ratio in case of neutral flame by weight is 3 ∶ 1

1 mole of O₂ = 31.99 grams

1 mole of C₂H₂ = 26.037 grams

So for neutral flame,

The ratio O₂/C₂H₂ = 1 ∶ 1 = \(\rm \dfrac{2.5~mole~O_2}{1~mole ~of~ C_2H_2}\)

C₂H₂ + \(\rm\dfrac{5}{2}O_2\) → 2CO₂ + H₂O

For neutral flame, 1 mole of C₂H₂ = 2.5 moles of O₂

1 mole of C2H2 = 26.037 grams

2.5 moles of O2 = 2.5 × 31.99 grams

Weight of O₂ ∶ C₂H₂ = 3 ∶ 1