Correct Answer - Option 4 : In(a) In(b)
Concept:
Evaluation of Double integrals: It doesn’t matter which variable we integrate with respect to first, we will get the same answer regardless of the order of integration.
\(\int {{\frac{{dx}}{{x}}} } = ln (x) + c\)
Calculation:
Given:
I = \(\int_1^a {\int_1^b {\frac{{dxdy}}{{x\,y}}} } \)
= \(\int_1^a {{\frac{{dx}}{{x}}} × \int_1^b {\frac{{dy}}{{y}}} } \)
= | ln (x) |1 to a × | ln (y) |1 to b
= [ln (a) - ln (1)] × [ln(b) - ln(1)]
I = ln (a) ln (b)