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The value of λ for which the system of equations 2x - y - z = 2, x - 2y + z = -4, x + y + λz = 4 has no solution, is:

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Correct Answer - Option 2 : -2

Given:

2x - y - z = 2,

x - 2y + z = -4,

x + y + λz = 4

Concept:

Consider the system of m linear equations

a11 x1 + a12 x2 + … + a1n xn = b1

a21 x1 + a22 x2 + … + a2n xn = b2

am1 x1 + am2 x2 + … + amn xn = bm

The above equations containing the n unknowns x1, x2, …, xn. To determine whether the above system of equations is consistent or not, we need to find the rank of the following matrices.

\(A = \left[ {\begin{array}{*{20}{c}} {{a_{11}}}&{{a_{12}}}& \ldots &{{a_{1n}}}\\ {{a_{21}}}&{{a_{22}}}& \ldots &{{a_{2n}}}\\ \ldots & \ldots & \ldots & \ldots \\ {{a_{m1}}}&{{a_{m2}}}& \ldots &{{a_{mn}}} \end{array}} \right]\) and  \(\left[ {A{\rm{|}}B} \right] = \left[ {\begin{array}{*{20}{c}} {{a_{11}}}&{{a_{12}}}& \ldots &{{a_{1n}}}&{{b_1}}\\ {{a_{21}}}&{{a_{22}}}& \ldots &{{a_{2n}}}&{{b_2}}\\ \ldots & \ldots & \ldots & \ldots & \ldots \\ {{a_{m1}}}&{{a_{m2}}}& \ldots &{{a_{mn}}}&{{b_m}} \end{array}} \right]\)

A is the coefficient matrix and [A|B] is called an augmented matrix of the given system of equations.

If the rank of matrix A is not equal to rank of augmented matrix, then system is inconsistent, and it has no solution.

Rank of A ≠ Rank of augmented matrix. Therefore if det (A) = 0 system is inconsistent (no solution)

Calculation:

\( A = \left[ {\begin{array}{*{20}{c}} 2&{ - 1}&{ - 1}\\ 1&{ - 2}&1\\ 1&1&λ \end{array}} \right]\;\;B = \left[ {\begin{array}{*{20}{c}} x\\ y\\ z \end{array}} \right]\;C = \left[ {\begin{array}{*{20}{c}} 2\\ { - 4}\\ 4 \end{array}} \right] \)

Hence, for no solution, |A| = 0

\( ⇒ \left| {\begin{array}{*{20}{c}} 2&{ - 1}&{ - 1}\\ 1&{ - 2}&1\\ 1&1&λ \end{array}} \right|\; = 0 \)

⇒ 2(-2λ - 1) + 1(λ - 1) - 1(1 + 2) = 0

⇒ -4λ - 2 + λ - 1 - 3 = 0

⇒ -3λ = 6

⇒ λ  = - 2


  • If the rank of matrix A is equal to the rank of an augmented matrix and it is equal to a number of unknowns, then system is consistent and there is a unique solution.
  • Rank of A = Rank of augmented matrix = n
  • If the rank of matrix A is equal to rank of augmented matrix and it is less than the number of unknowns, then system is consistent and there are infinite number of solutions.
  • Rank of A = Rank of augmented matrix < n

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