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The maximum value of sin θ - cos θ is 
1. 2
2. \(\frac{\sqrt{3}+1}{2}\)
3. √2
4. 1

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Correct Answer - Option 3 : √2

Concept:

The maximum value of \(a\sin x + b \cos x = √ { a^2 + b^2}\)

Calculation:

The maximum value of sin θ - cos θ = \(\sqrt {1^2+(-1)^2}= \sqrt{2}\)

Hence, the maximum value is √2.

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