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If log2 = 0.3010 and log 3 = 0.4771, then the value of log 6 is
1. 0.8177
2. 0.7781
3. 0.6781
4. 0.7681

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Correct Answer - Option 2 : 0.7781

Given:
log 2 = 0.3010

log 3 = 0.4771

Formula used:

log (x × y) = log x + log y

Calculation:

log 6 = log (2.3)

⇒ log (2.3) = log 2 + log 3

⇒ log (2.3) = 0.3010 + 0.4771 = 0.7781

∴ log 6 = 0.7781.

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