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\(\rm cot^{-1}{1\over3} - 2 \tan^{-1}{2\over3} = ?\)
1. 1
2. -1
3. \(\rm \cot^{-1}{41\over3}\)
4. \(\rm \tan^{-1}{41\over3}\)

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Best answer
Correct Answer - Option 3 : \(\rm \cot^{-1}{41\over3}\)

Concept:

  • \(\rm \tan^{-1}x + \tan^{-1}y=\tan^{-1}{x+y\over 1-xy}\)
  • \(\rm cot^{-1}{x} = {\pi\over2}- \tan^{-1}{x}\)
  • \(\rm 2tan^{-1}\ x =tan^{-1} ({\frac {2x}{1\ -\ x^2}})\)


Calculation:

S = \(\rm cot^{-1}{1\over3} - 2 \tan^{-1}{2\over3} \)

S = \(\rm \left[{\pi\over2}-\tan^{-1}{1\over3}\right] - \tan^{-1}{{2\over3}+{2\over3}\over1-{2\over3}\times{2\over3}}\)

S = \(\rm {\pi\over2}- \left[ \tan^{-1}{12\over5}+\tan^{-1}{1\over3}\right]\)

S = \(\rm {\pi\over2}- \left[ \tan^{-1}{{12\over5}+{1\over3}\over1-{12\over5}\times{1\over3}}\right]\)

S = \(\rm {\pi\over2}- \left[ \tan^{-1}{41\over3}\right]\)

S = \(\rm \cot^{-1}{41\over3}\)

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