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If P(A) = 6/11, P(B) = 5/11 and P(A ∪ B) = 7/11 then P(A | B) = ?


1.

\(\frac{4}{5}\)


2.

\(\frac{3}{5}\)


3.

\(\frac{5}{7}\)


4.

\(\frac{3}{7}\)

1 Answer

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Best answer
Correct Answer - Option 1 :

\(\frac{4}{5}\)


Concept:

Conditional Probability:

The probability of an event occurring given that another event has already occurred is called a conditional probability.

  • P(A ∩ B) = P(A) x P(B | A) = P(B) x P(A | B) where P(A | B) represents the conditional probability of A given B and P (A | B) represents the conditional probability of A given B.

Calculation:

Given: P(A) = 6/11, P(B) = 5/11 and P(A ∪ B) = 7/11

As we know that, P(A ∪ B) = P(A) + P(B)  - P(A  B)

So, by substituting the given values in the above formula we get,

 \(\Rightarrow \rm \frac{7}{11}=\frac{6}{11}+\frac{5}{11}-P(A\cap B)\)

\(\Rightarrow \rm P(A\cap B)=\frac{4}{11}\)

As we know that, P(A ∩ B) = P(A) x P(B | A) = P(B) x P(A | B)

\(\Rightarrow \rm P(A | B) =\frac{P(A\cap B)}{P(B)}=\frac{\frac{4}{11}}{\frac{5}{11}}=\frac{4}{5}\)

Hence, option 1 is the correct answer.

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