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Compute P(A ∪ B), if 2P(A) = P(B) = 5/13 and P(A | B) = 2/5 ?


1.

\(\frac{13}{26}\)


2.

\(\frac{15}{26}\)


3.

\(\frac{17}{26}\)


4.

\(\frac{11}{26}\)

1 Answer

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Best answer
Correct Answer - Option 4 :

\(\frac{11}{26}\)


Concept:

Conditional Probability:

The probability of an event occurring given that another event has already occurred is called a conditional probability.

  • P(A ∩ B) = P(A) x P(B | A) = P(B) x P(A | B) where P(A | B) represents the conditional probability of A given B and P (A | B) represents the conditional probability of A given B.

Calculation:

Given: 2P(A) = P(B) = 5/13 and P(A | B) = 2/5 

As we know that, P(A ∩ B) = P(A) x P(B | A) = P(B) x P(A | B)

\(⇒ \rm P(A | B) =\frac{P(A\cap B)}{P(B)}⇒ \frac{2}{5}=\frac{P(A\cap B)}{\frac{5}{13}}⇒ P(A\cap B)=\frac{2}{13} \)

∵ 2P(A) = 5/13 ⇒ P(A) =5/26

As we know that, P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

\(\Rightarrow \rm P(A \cup B) =\frac{5}{26}+\frac{5}{13}-\frac{2}{13}⇒ P(A \cup B)=\frac{11}{26}\)

Hence, option 4 is the correct answer.

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