(a) The fixed pulley P2 only changes the direction of the force i.e. force can be applied downwards which is more convenient.
(b) The load will be raised by a distance x/2.
(c) Distance moved by load dL = x/2
Distance moved by the effort dE = x
Load (L) = 20 kgf
Effort = ?
Load × Load arm = effort × effort arm
20 x x/2 = x x E or E = 10kgf.