Correct Answer - Option 2 : 0.05% of the full range
Concept:
The resolution (R) in an N bit DVM is given by:
\(R= \frac{1}{{{{10}^N}}} \;\)× range of the voltmeter
Where N is the number of full digits.
In a DVM, a full digit counts 0 to 9 and a half digit counts from 0 to 1.
For N and half DVM resolution (R) is given by:
\(R= \frac{1}{{2\times{{10}^N}}} \;\)× range of the voltmeter
Calculation:
Given that,
N = 3(1/2)
\(R = \frac{1}{ 2 \times 10^3}\) × of the full range
%R = (1/2000) × 100 × of full range
%R = 0.05 % of full range
By applying the \(R= \frac{1}{{{{10}^N}}} \;\)× range of the voltmeter
Which will give
%R = (1/1000) × 100 × of full range
%R = 0.1 % of full range
Will be INCORRECT as it is only applicable for 3 digit voltmeter.
