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Two signals of frequency 1 Hz each are applied to the X and Y plates of an oscilloscope. If the time interval between the zero crossings of the two signals is 100 ms, then the phase difference between the signals is
1. 18°
2. 36°
3. 72°
4. 144°

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Correct Answer - Option 2 : 36°

Oscilloscope:

  • An oscilloscope display voltage or current as a function of time.
  • The sweep generation provides a periodic voltage waveform that varies with time.
  • When sweep and signal frequencies are equal, a single cycle appears on the screen.
  • When the sweep frequency is lower than the signal frequency, several cycles appear on the screen.
  • When the sweep frequency is higher than the signal frequency, less than one cycle appears.
  • The display of the spot on the screen appears stationary only when the two frequencies i.e. sweep and signal are the same or integral multiples of each other.
  • 1 Time period is the time taken to complete one-cycle or 360° electrical.  

 

Time period (T) is inverse of frequency (f)

\(T = \frac{1}{f}\)

Calculation:

Given:

f = 1 Hz

\(T = \frac{1}{f} = \frac{1}{1} = 1 = 1000\;ms\)

1000 ms ↔ 360°

\(100\;ms \leftrightarrow \frac{{360^\circ }}{{1000\;ms}} \times 100\;ms = 36^\circ \)

The phase difference between the signal is 36°.

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