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There are eight cars A, B, C, D, E, F, G and H. Each car has a different price. Price of C is more than that of A and D. Price of at least two cars is less than A. Price of F is more than that of G and H. Price of D is less than G, but more than E. Price of B is less than H, but more than G. Price of at least four cars is more than that of C. Which of the following sequence is correct?
1. F > H > B > G > C > A > D > E
2. F > H > G > B > C > A > D > E
3. F > H > B > G > C > A > E > D
4. F > H > B > G > C > D > A > E

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Correct Answer - Option 1 : F > H > B > G > C > A > D > E

Eight cars: A, B, C, D, E, F, G and H.

1) Price of C is more than that of A and D.

C > A/D

2) Price of at least two cars is less than A.

A > _ > _

3) Price of F is more than that of G and H.

F > G/H

4) Price of D is less than G, but more than E.

G > D > E

5) Price of B is less than H, but more than G.

H > B > G

6) Price of at least four cars is more than that of C. 

_ > _ > _ > _ > C

From all the statements;

F > H > B > G > C > A > D > E

Hence, option (4) is the correct answer.

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