Correct Answer - Option 1 : 133
GIVEN:
Three numbers 2800, 2401 and 1470.
CALCULATION:
Let same remainder = ‘x’
Required maximum number = HCF of (2800 – x), (2401 – x) and (1470 – x)
We know that if two numbers be divisible by a certain number, then their difference is also divisible by that number.
HCF of (2800 – x), (2401 – x) and (1470 – x) = HCF of [(2800 – x) – (2401 – x)], [(2800 – x) – (1470 – x)] and [(2401 – x) – (1470 – x)] = HCF of 399, 1330 and 931 = 133
Hence, required greatest number = 133