Correct Answer - Option 5 : x = y OR relation between x and y can not be established.
Calculation:
l. x2 – 3x – 4 = 0
⇒ x2 – 4x + x – 4 = 0
⇒ x(x – 4) + 1(x – 4) = 0
⇒ (x – 4) (x + 1) = 0
⇒ x = 4, -1.
ll. y2 – 5y – 6 = 0
⇒ y2 – 6y + y – 6 = 0
⇒ y(y – 6) + 1(y – 6) = 0
⇒ (y + 1) (y – 6) = 0
⇒ y = 6, -1.
Comparison between x and y (via Tabulation):
Value of x
|
Value of y
|
Relation
|
4
|
6
|
x < y
|
4
|
-1
|
x > y
|
-1
|
6
|
x < y
|
-1
|
-1
|
x = y
|
∴ The relation between x and y can not be established.