Question

Directions: In the following question, two statements are numbered as Quantity I and Quantity II. On solving these statements, we get quantities I and II respectively. Solve both quantities and choose the correct option.

In a mixture of milk and water, the quantity of water is 25% less than the quantity of milk. When 10 liters of pure milk were added then the quantity of milk becomes 60% more than the quantity of water. 

Quantity I: What is the quantity of water in the mixture?

Quantity II: 40 litres
1. Quantity 1 > Quantity 2
2. Quantity 1 ≥ Quantity 2
3. Quantity 1 < Quantity 2
4. Quantity 1 ≤ Quantity 2
5. Quantity 1 = Quantity 2

Answer 1

Correct Answer - Option 3 : Quantity 1 < Quantity 2

Given:

Q water = 25% less than Q milk

Calculation:

Let the quantity of milk = 100x litres

⇒ Quantity of water = (100 – 25)% of 100x 

⇒ 75% of 100x = 75x litres 

When 10 litres of milk was added then the quantity of milk = 100x + 10 litres and the quantity of water = 75x litres 

According to the question,

⇒ 160% of 75x = (100x + 10) 

⇒ 120x = 100x + 10

⇒ 20x = 10

⇒ x = 0.5 litres 

Quantity I:

The quantity of water = 75x

⇒ 75 × 0.5 = 37.5 litres 

Quantity II = 40 litres

∴ Quantity I < Quantity II