Correct Answer - Option 4 : mm
3
Explanation:
Sectional Modulus (Z):
It is the ratio of Moment of Inertia (I) of the beam cross-section about the neutral axis to the distance (ymax) of extreme fiber from the neutral axis.
For a circular section, the section modulus:
\(Z = \frac{I}{y_{max}}\)
where \(I=\frac{\pi}{64} d^4\) = Moment of Inertia.
y = distance from the centroid to top or bottom edge i.e. y = \(\frac{d}{2}\)
\(Z_{cirular\;section}=\frac{I}{y_{max}}\)
\(Z_{cirular\;section}=\frac{\frac{\pi{d^4}}{64}}{\frac{d}{2}}\)
\(Z_{cirular\;section}=\frac{\pi{d^3}}{32}\)
It can be seen that Z ∝ d3
∴ the unit of the section modulus is mm3.